4^3+1^=65.. 2^3+3^3=35..
So (-3)^3+x^3=4
Which means -27 + x^3 = 4
So x^3 = 31
And x = cube root of 31
This is NOT a very satisfying answer.
[math]37[/math]
The second number in each triple is the sum of the cubes of the first and the third.
[math]4^{3} + 1^{3} = 64 + 1 = 65[/math]
[math]2^{3} + 3^{3} = 8 + 27 = 35[/math]
[math](-3)^{3} + 4^{3} = -27 + 64 = 37[/math]
-11
Pattern: first digit of second number is first number plus two (so -3 plus 2 is -1) and second digit of second number is first number plus third number (so -3 plus 4 is 1)
I’ll bet there are other “second numbers” that also fit, that’s just the one that first occurred to me, and when I checked it it appeared to work.
Answer is 49 because
2×2=4
3×3=9
4×4=16
5×5=25
6×6=36
7×7=49 is missing number and this is right answer
8×8=64
I don't think there is a missing number.
First number—second number—difference
3–5–2
5–9–4
9–15–6
15–23–8
23–33–10
As you can see the difference between each number and the next is the nth multiple of 2. It starts at 2 and grows by 2 each step.
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16;
1;
6;
There are two series in the given sequenc;
For odd position numbers;
Series goes like this :1,2,3,4,5,6,7,8……
For even position numbers;
Series goes like this:
1,4,16,25,36,49,64……(square ⬜ of odd position numbers )
So our main series is:1,1,2,4,3,9,4,16,5,25,6,36,7,49,8,64…….
However this is not the single answer to this question,Always there are thousands of answers to such question,some little bit more accurate some less.
So let's find other answers:
1,1*,2,4*,3,9*,4,1*,5,4*,6,9*,7,1*,8,4*…..(Assuming 1,4,9 repeats in the even position)
1,1*,2,4*,3,9*,4,6*,5,5*,6,6*,7,9*,8,4*…..
(Using the righ
16;
1;
6;
There are two series in the given sequenc;
For odd position numbers;
Series goes like this :1,2,3,4,5,6,7,8……
For even position numbers;
Series goes like this:
1,4,16,25,36,49,64……(square ⬜ of odd position numbers )
So our main series is:1,1,2,4,3,9,4,16,5,25,6,36,7,49,8,64…….
However this is not the single answer to this question,Always there are thousands of answers to such question,some little bit more accurate some less.
So let's find other answers:
1,1*,2,4*,3,9*,4,1*,5,4*,6,9*,7,1*,8,4*…..(Assuming 1,4,9 repeats in the even position)
1,1*,2,4*,3,9*,4,6*,5,5*,6,6*,7,9*,8,4*…..
(Using the right digit of square ⬜ of odd position numbers in the even position )
You can go on and on....
Hope this answers the question.
If you like it.Please upvote, Follow the question and be with Quora. It doesn't cost any, Does it!
The answer is 33.
Methodology:
3*2 = 6 & 6–1 = 5
5*2 = 10 & 10–1 = 9
9*2 = 18 & 18–1 = 17
So now,
17*2 = 34 & 34–1 = 33.
Similarly,
33*2 = 66 & 66–1 = 65
And I think the last one can be done easily to verify.
Hope this helps you.
Shukriya :)
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Solution:
Given; 3, 5, 9, 17, __ , 65, 129
a1 = 3
a2 = a1 + 2 X 1= 3 + 2 = 5
a3 = a2 + 2 X 2 = 5 + 4 = 9
a4 = a3 + 2 X 4 = 9 + 8 = 17
a5 = a4 + 2 X 8 = 17 + 16 = 33
a6 = a5 + 2 X 16 = 33 + 32 = 65
a7 = a6 + 2 X 32 = 65 + 64 = 129
a8 = a7 + 2 X 64 = 129 + 128 = 257
Therefore, the missing number in the sequence 3, 5, 9, 17, __ , 65, 129 is 65. …… Answer
You add 3,5,7,9,11, 13 etc..
1+0=1
1+3=4
4+5=9
9+7=16
16+9=25
25+11=36
36+13=49
Answer: 75
You make a 3 digit number out of the top left, then top right, then bottom right numbers, and divide that number by the bottom left number.
For instance, the solution for the first block would be 246/6 = 41
The solution for the second block would be 364/7 = 52
So, the solution for the third block would be 375/5 = 75
I would say the next number in the series is 52, following this pattern:
The first, third, fifth and seventh members of the series (the odd positions) all increase by 8.
The second, fourth and sixth members (even positions) all increase by 15.
Thus, 2+8=10, 10+8=18, 18+8=26
And 7+15=22, 22+15=37
So finally, 37+15=52.
6
This pattern looks like it follows the 4th row of Pascal’s triangle (the top row is the 0th row)
image source: https://artofproblemsolving.com/wiki/index.php?title=Pascal%27s_triangle
6
This pattern looks like it follows the 4th row of Pascal’s triangle (the top row is the 0th row)
image source: https://artofproblemsolving.com/wiki/index.php?title=Pascal%27s_triangle
49
because the series is following the square of numbers
like,
4 = 2*2
9=3*3
16=4*4
.
.
.
so the series is Square of(2,3,4,5,6,7,8)
and the square of 7 is missing so 49.
97 ,65 ,49 ,41 ,? ,35
97, 65, 49, 41, x, 35
Step 1 : 97–65 = 32,
32 = 16*2
Step 2 : 65–49 = 16,
16 = 8*2
Step 3 : 49–41 = 8,
8=4*2
Step 4 : 41-x=y
y=4
because 4 = 2*2
Step 5 : 41-x=4
x=41–4=37
x=37
final series is 97, 65, 49, 41, 37, 35
Any of them can be the right answer.
For 36 the pattern: 77/4 * top left - 13/2 * top right + 19/4 * bottom left = middle.
For 48 the pattern: -19/4 * top left + 11/2 * top right + 19/4 * bottom left = middle.
For 75 the pattern: -235/4 * top left + 65/2 * top right + 19/4 * bottom left = middle.
For 50 the pattern: -35/4 * top left + 15/2 * top right + 19/4 * bottom left = middle.
For 47 the pattern: -11/4 * top left + 9/2 * top right + 19/4 * bottom left = middle.
And we didn't even use the bottom right number.
Hello,
First, alculate the difference between each number. For example: 3 and 4 the diff is 1, for 4 and 8 it will be 4, for 8 and 17 it will be 9 and 17 and 33 it will be 16.
1st result: 1 which is 1^2. (3+1=4)
2ns result: 4 which is 2^2. (4+4=8)
3rd result: 9 which is 3^2. (8+9=17)
4th result: 16 which is 4^2. (17+16=33)
So 5th result will be 25 ( 5^2). Adding that to 33 yields 58.
6th result: 36 (6^2). Adding that to 58 yields 94.
7th result: 49 (7^2). Adding that to 94 yields 143.
Finally,
The sequence will be 3,4,8,17,33,58,94,143…
For problems like these, start from left to right and start analyzin
Hello,
First, alculate the difference between each number. For example: 3 and 4 the diff is 1, for 4 and 8 it will be 4, for 8 and 17 it will be 9 and 17 and 33 it will be 16.
1st result: 1 which is 1^2. (3+1=4)
2ns result: 4 which is 2^2. (4+4=8)
3rd result: 9 which is 3^2. (8+9=17)
4th result: 16 which is 4^2. (17+16=33)
So 5th result will be 25 ( 5^2). Adding that to 33 yields 58.
6th result: 36 (6^2). Adding that to 58 yields 94.
7th result: 49 (7^2). Adding that to 94 yields 143.
Finally,
The sequence will be 3,4,8,17,33,58,94,143…
For problems like these, start from left to right and start analyzing using the 4 operations (+×÷-). Mostly you will find your sequence from these unless it involves other operations like sqrt and vice versa.
Good Luck!
You may call this a silly try, but I don't really mind, actually I don't believe that this type of questions measures one's smartness at all , , blabla anyways...
We do notice that the number 7 is there in all the middle numbers! fortunately it is present in all the choices too! good, I can deduce that there is no reason to bother on how to generate 7 (or 7 hundred ...)
we are left with two digits to be generated using 3 given digits (we may not use all of them, I don't see any restriction on that matter)
so, how to obtain :
28 using 5, 5, 6
31 using 8, 6, 8
xx using 9, 7, 8
?
back to my apparent magi
You may call this a silly try, but I don't really mind, actually I don't believe that this type of questions measures one's smartness at all , , blabla anyways...
We do notice that the number 7 is there in all the middle numbers! fortunately it is present in all the choices too! good, I can deduce that there is no reason to bother on how to generate 7 (or 7 hundred ...)
we are left with two digits to be generated using 3 given digits (we may not use all of them, I don't see any restriction on that matter)
so, how to obtain :
28 using 5, 5, 6
31 using 8, 6, 8
xx using 9, 7, 8
?
back to my apparent magic number, 7
first combination:
7 + 5 = 12 (12 mod 10 = 2 )
12 + 6 = 18 (18 mod 10 = 8 )
wow, I got 28 using 5 and 6 from the first combination
second combination: (same logic)
7 + 6 = 13 (13 mod 10 = 3 )
13 + 8 = 21 (21 mod 10 = 1 )
wow, I got 31 using 5 and 6 from the second combination
If we apply the same logic on the third combination (9,7,8), starting with 7 (magic digit) and adding then taking modulus of 10 we can have the following possible two digit numbers (we only use to numbers out of the given three, like we did above):
42, 43, 64, 63, 52, 54
guess which unique number is given in the choices?!
Well this could be totally dumb answer, but again, this type of questions is open for any possible creativity , especially with no additional information, restrictions, hints ...
These number are the squares of 2,3,4,5,6 and 8. If one is looking for only one number missing then one would say 49, which is 7 squared, but I think the sequence would look complete if you also add 1 as a start to this sequence being the square of 1. And with this second missing piece now the sequence has an identity; squares of integers. The sequence would look like:
1,4,16,25,36,49,64,…
The dots at the end indicates this sequence can go endlessly as squares of integers.
Edit: I replaced “positive integers” with just “integers” since sqauring negative integers will also result into the same seq
These number are the squares of 2,3,4,5,6 and 8. If one is looking for only one number missing then one would say 49, which is 7 squared, but I think the sequence would look complete if you also add 1 as a start to this sequence being the square of 1. And with this second missing piece now the sequence has an identity; squares of integers. The sequence would look like:
1,4,16,25,36,49,64,…
The dots at the end indicates this sequence can go endlessly as squares of integers.
Edit: I replaced “positive integers” with just “integers” since sqauring negative integers will also result into the same sequence.
Hope this helps.
a(n4)=32
The series 4,8,16,__,64 shows a missing number x followed by the number 64
PATTERN
The series reveals a logically deductive pattern which can be objectified by an algorithm allowing us to determine the nth value of any term in the series whether or not the previous term is known.
ALGORITHM
The value of every nth term of the series=a(n)=2^(n+1), where n=the term's position in the series=(2^a), where “a” starts @ 2 and increases by 1 each successive term and where “2” is a constant base:
(1) 2^2=4
(2) 2^3=8
(3) 2^4=16
(4) 2^5=32 (the missing number a(n4) ***
(5) 2^6=64
(6) 2^7=128
(7) 2^8=256
(8) 2^
a(n4)=32
The series 4,8,16,__,64 shows a missing number x followed by the number 64
PATTERN
The series reveals a logically deductive pattern which can be objectified by an algorithm allowing us to determine the nth value of any term in the series whether or not the previous term is known.
ALGORITHM
The value of every nth term of the series=a(n)=2^(n+1), where n=the term's position in the series=(2^a), where “a” starts @ 2 and increases by 1 each successive term and where “2” is a constant base:
(1) 2^2=4
(2) 2^3=8
(3) 2^4=16
(4) 2^5=32 (the missing number a(n4) ***
(5) 2^6=64
(6) 2^7=128
(7) 2^8=256
(8) 2^9=512
(9) 2^10=1024
(10) 2^11=2048 and so forth, …
(25) 2^(25+1)=2^26=67,108,864
4, 8, 16, 32, 64, 128, 256, 512, 1024, 2048, 4096, 8192, 16,384, 32,768, 65,536, 131,072, 262,144, 524,288, 1,048,576, 2,097,152, 4,194,304, 8,388,608, 16,777,216, 33,554,432, 67,108,864, 134,217,728,…to +infinity.
C.H.
16.
Split the sequence into 2 alternating sequences:
1,2,3,4
This is simply a sequence of increasing natural numbers.
1,4,9,?
The first sequence is just increament of 1 in the previous no. The second is a sequence of perfect square numbers. So, the next term is 4^2, That is 16.
75
there is a pattern in the above question
box 1 246/6= 41
box 2 364/7= 52
box 3 375/5= 75
its because of the above pattern the answer can be deduced as 75
7
If x is 0 and decreasing
and y is 2 and increasing
and they add up and alternate to the numbers you get:
1 + x(0) = 1; x--
1 + y(2) = 3; y++
3 + x(-1) = 2; x--
2 + y(3) = 5; y++
5 + x(-2) = 3; x--
3 + y(4) = 7
4,3,6
The nth term in the sequence has the number of letters in n written out.
For example, “one” has 3 letters, so the first number in the sequence is 3
“two” has three letters as well, so the second digit is 3 as well.
“three” has 5 digits, so the third term in the sequence in 5
We can see that this pattern works for integers 1–8
Then, we see that “Nine”, “Ten”, and “Eleven”, have 4, 3, and 6 letters, so our answer is 4,3,6
In this series there are no missing numbers. However the series continues with these numbers:
Ans: 216, 23
There are 2 series of numbers
series 1:
3, 5, 8, 12, 17, 23…
numbers 2, 3, 4, 5, 6, added to each number respectively in this serie.
Series 2:
8, 27, 64, 125, 216….
these are cubes of 2, 3, 4, 5, 6…
There is NO correct answer to this question. There are INFINITELY many arrangements of numbers that can have these three numbers in this sequence. Some finite collection of numbers is simply insufficient to define ALL the numbers in the sequence. Pick any numbers you like and demonstrate their relationship with the first three numbers and you should get 100% marks on the problem.
Some will argue, well, yes, but this is the simplest or most obvious. That is false. These things cannot be defined.
It is only a game to see if you can come up with whatever the question writer had in his/her head at t
There is NO correct answer to this question. There are INFINITELY many arrangements of numbers that can have these three numbers in this sequence. Some finite collection of numbers is simply insufficient to define ALL the numbers in the sequence. Pick any numbers you like and demonstrate their relationship with the first three numbers and you should get 100% marks on the problem.
Some will argue, well, yes, but this is the simplest or most obvious. That is false. These things cannot be defined.
It is only a game to see if you can come up with whatever the question writer had in his/her head at the time the question was written. Don’t fall for it. When the question is, “Guess what’s in my head.” That is not a legitimate question. Perhaps it is okay on a daily assignment, just to generate this conversation, but it never would be appropriate on an examination.
If the question had said something like this, “Use constant forward differences of order 1 to fill in the next two blanks in the following partial sequence.” That would be a better question with a tractable answer.
a(n1, n3, n5)=374, 402, 430
PREMISES
S=__, 388, __, 416, __, 444,… Note: 415 appears to be out of place while 416 is consistent with the pattern
A partial sequence S shows a pattern from left to right where the terms increase by a common difference d
ALGORITHM
a(n)=(n-1)+d, where n=any nth ordinal term in the sequence, n-1=the prior term, and where d=a common difference (444–388)/4=14
PATTERN
(0) 346+14=360
(1) 360+14=374 [ANSWER]
(2) 374+14=388
(3) 388+14=402 [ANSWER]
(4) 402+14=416
(5) 416+14=430 [ANSWER]
(6) 430+14=444
(7) 444+14=458
(8) 458+14=472
(9) 472+14=486
(10) 486+14=500
and so on
C.H.
33.
From 3 to 5, you add 2
From 5 to 9, you add 4
From 9 to 17, you add 8
From 17 to 33, you add 16
From 33 to 65, you add 32
From 65 to 129, you add 64
so on.
It is adding by the power of 2.
First it’s 2^1 then 2^2, then 2^3, then so on.
I guess you asked what’ll be the next number in the given series. In that case the answer is 58.
Here is the explanation:
The given series is 3, 4, 8, 17, 33 and the number follow the following pattern:
[math]3 + 1^2 = 4[/math]
[math]4 + 2^2 = 8[/math]
[math]8 + 3^2 = 17[/math]
[math]17 + 4^2 = 33[/math]
Hence the next number will be
[math]33 + 5^2 = 58.[/math]
13 = 3*2 + 7
46 = 3*13 + 7
I'm guessing that the rule defining the sequence is s(n+1) = 3*s(n) + 7, where s(n) is the nth member.
Using this, the next member would be 3*46 + 7 = 145
The one after that would be 3*145 + 7 = 442, which fits.
So the missing number is 145.
The answer is 1, 6, 6.
3 - 3 - 5 - 4 - 4 - 3 - 5 - 5 - _ - _ -_
3+3+5=11
4+4+3=11
5+5+1=11
6+6-1=11
The answer is 73.
Here, the numbers are getting reduced in a pattern.
The pattern is:
85–84= 1
84–80= 4
80-x = 7
x-63= 10
63–50= 13
50–34 = 16
This series of 1,4,7,10,13,16 is an Arithmetic Progression.
Happy Learning. Thanks.
Hye,
The next number is 13.
This sequence consists of numbers which are sum of digits of 2^n.
For example: when n= 1, 2^n is 2 which is the first number of sequence.
When n=6, 2^6=64. So,6+4=10 which is sixth number of sequence.
So, when n=8, 2^8=256,So, 2+5+6=13 which will be the eighth number of sequence.
Hope this helps :)
I hope you like the answer.✌
Thanks for asking🙋
I hope you like the answer.✌
Thanks for asking🙋